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Re: oooooh, I am so evil.....
Posted: Fri Dec 28, 2012 11:28 pm
by Remedy™
Dubby_CompGamerGeek2 wrote:lulz, but it took over 4.5 hours for that conclusion to be determined, proved, and verified.
and that is if we don't wait for me to show up and agree with you.
Lack of caring? Look at the amount of time in between posts.
Re: oooooh, I am so evil.....
Posted: Sat Dec 29, 2012 12:03 am
by Psyko
It only took 14 posts...
Re: oooooh, I am so evil.....
Posted: Sat Dec 29, 2012 12:30 am
by ƒëmmë
x = pineapple
cba doing the whole BIMDAS stuff,
bacon is good
ex's are bad
Re: oooooh, I am so evil.....
Posted: Sat Dec 29, 2012 1:28 am
by JasonJay
Brackets first
Division and multiplication are of equal importance
Therefore 6/2(2+1)=1
As 6/(2*3)=1
In general we were taught to bracket the denominator and numerator to simplify either on it's own before doing overall simplification
Re: oooooh, I am so evil.....
Posted: Sat Dec 29, 2012 6:48 am
by Remedy™
JasonJay wrote:Brackets first
Division and multiplication are of equal importance
Therefore 6/2(2+1)=1
As 6/(2*3)=1
In general we were taught to bracket the denominator and numerator to simplify either on it's own before doing overall simplification
The 6/2 goes first as...
JasonJay wrote:Division and multiplication are of equal importance
So, 6/2 = 3
3(3) = 9
Thought we already explained this.
Order or operations:
http://en.wikipedia.org/wiki/Order_of_operationsBrackets, then Mult/Div(left to right)
6/2
(2+1)=x
6/2(3)=x
3(3)=x
x=9
Re: oooooh, I am so evil.....
Posted: Sat Dec 29, 2012 10:01 am
by JasonJay
It hit me, don't change your denominators into numerators
6/2(2+1)=1 as it can be written as (6/1)*(1/3)*[1/(2+1)]
(6/2)(2+1)=9 as this can be written as (6/1)*(1/3)*[(2+1)/1]
*flies away*
Re: oooooh, I am so evil.....
Posted: Sat Dec 29, 2012 10:05 am
by Remedy™
JasonJay wrote:It hit me, don't change your denominators into numerators
6/2(2+1)=1 as it can be written as (6/1)*(1/3)*[1/(2+1)]
(6/2)(2+1)=9 as this can be written as (6/1)*(1/3)*[(2+1)/1]
*flies away*
How exactly are you getting those...?
6/1 I get.
[(2+1)/1] I get
But, you are doing 1/3 for the number 2 for some reason.
Also...
(6/1)*(1/3)*[(2+1)/1] = 6, not 9
Re: oooooh, I am so evil.....
Posted: Sat Dec 29, 2012 10:07 am
by JasonJay
1/2*
Lulz the second answers is irrelevant to the point
So accept my proof or must I break out the math laws?
Re: oooooh, I am so evil.....
Posted: Sat Dec 29, 2012 5:17 pm
by Slim87R
Yup evil me. The answer should be 9 any way you cut it.
6/2(1+2)
6/2 is a fraction applied to (1+2),
so if you wer to do it the distributive way you would end up with
(6/2)*1+(6/2)*2
(6/2)+(12/2)
18/2
9
or
6/2(3)
6/2*3 --The number in the parenthsis has been simplified so they are no longer relevant
3*3
9
New challenge replace any number with X to proof it.
ex:6/2(X+2)=9
or:X/2(1+2)=9
See if X comes out to 1 in the first and 6 in the 2nd.
Re: oooooh, I am so evil.....
Posted: Sat Dec 29, 2012 5:35 pm
by Neimenljivi
Actually the formula is written incorrectly from the start.
The correct way, to get the solution you deem is right, would be to write:
(6/2)(1+2)=X
6/2(1+2)=X can mean either the formula above, indicating X=9 (the solution you deem right) or the formula 6/(2(1+2)) = X meaning X=1
So it all comes down to whether the fraction 6/2 is multiplied by (1+2) or the (1+2) is part of the denominator in which case 6 is divided by (2(1+2)).
~N
Re: oooooh, I am so evil.....
Posted: Sat Dec 29, 2012 5:45 pm
by Slim87R
Neimenljivi wrote:Actually the formula is written incorrectly from the start.
The correct way, to get the solution you deem is right, would be to write:
(6/2)(1+2)=X
6/2(1+2)=X can mean either the formula above, indicating X=9 (the solution you deem right) or the formula 6/(2(1+2)) = X meaning X=1
So it all comes down to whether the fraction 6/2 is multiplied by (1+2) or the (1+2) is part of the denominator in which case 6 is divided by (2(1+2)).
~N
You are absolutely right there. But what if "/" was replaced with the division symbol?
Edit:I read somewhere that the denominator can only be the element after the "/". So since it is written 6/2(1+2), 2 is the element that is the denominator. If the equation was written 6/(2(1+2)), then the element would be everything inside the parenthesis making the entire denominator 2(1+2).
Discuss.
Re: oooooh, I am so evil.....
Posted: Sat Dec 29, 2012 5:49 pm
by Neimenljivi
In computer science / is the division symbol
~N
Re: oooooh, I am so evil.....
Posted: Sat Dec 29, 2012 5:52 pm
by Slim87R
Neimenljivi wrote:In computer science / is the division symbol
~N
I hear that "/" is given a slightly higher rank than the division symbol. Discuss.
Re: oooooh, I am so evil.....
Posted: Sat Dec 29, 2012 6:04 pm
by Neimenljivi
Seeing your edit now, I'm sure you're familiar with the equation pV=nRT
Where the constant R=8,314 kPaL/Kmol - both K and mol are in denominator, I've never seen it written as kPaL/Kmol^-1 (I have, though, seen it written as kPaLK^-1mol^-1). So more elements can be considered as part of the denominator, depending on how the fraction is written of course. As I said, what you've written can have 2 solutions depending on what you take as the whole fraction. In straight-line writing, you have to use parenthesis. Calculators will use only the first element after the division symbol, but that's something that was decided upon. I've never, ever seen a rule saying that only the first element after the division symbol is taken into the denominator (R, seen in many literatures, proving my point as well).
As I said, in computer science the symbol for division is /, it doesn't "outrank" any other symbol afaik.
~N
Re: oooooh, I am so evil.....
Posted: Sat Dec 29, 2012 7:35 pm
by Slim87R
LMAO. I know almost nothing about math. I was just trolling. Not familiar with the equation you used as an example. I posted the equation from Facebook. Whoever originally wrote it like that is either an asshat or a troll himself. I just figured it would turn into a raging thread of 1 vs 9 like I saw on Facebook hence the "I'm evil" part.