I am trying to use a formula given in a game to work out planet population:
P = (Ln (Nbr Flats) x (Nbr Flats)2) + (Nbr Flats)
Where: Ln = Logarithm Neperian
Can anyone tell me what Logarithm Neperian? I can't finish it with out the figure for Ln.
Maths Question
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Grand Admiral Martin
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Nigatsu_Aka
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Re: Maths Question
Ln is the logarithm with aprox the base: e=2,71
e^ln(x)=x;
I hope this helps you figure what you`re looking for.
PS: ln is called natural logarithm.
e^ln(x)=x;
I hope this helps you figure what you`re looking for.
PS: ln is called natural logarithm.
Last edited by Nigatsu_Aka on Tue Jan 22, 2008 9:39 am, edited 1 time in total.
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Re: Maths Question
And:
ln*e=1
That's about the only thing I remember. My pre-calc teacher is awful...
ln*e=1
That's about the only thing I remember. My pre-calc teacher is awful...
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Mathlord
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Re: Maths Question
There is usually a natural log button on most calculators. It's just log base e as opposed to log base 10.
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Grand Admiral Martin
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Re: Maths Question
P = (Ln (220) x (220)2) + (220)
Where: Ln = Logarithm Neperian
P = (Ln (220) x (48,400) + (220)
Where: Ln = Logarithm Neperian
P = (Ln x 10,648,000) + (220)
Where: Ln = Logarithm Neperian
= ???
Can anyone finish that? I have tried but I must be doing something wrong answer doesn't match examples of what it should be close to.
Where: Ln = Logarithm Neperian
P = (Ln (220) x (48,400) + (220)
Where: Ln = Logarithm Neperian
P = (Ln x 10,648,000) + (220)
Where: Ln = Logarithm Neperian
= ???
Can anyone finish that? I have tried but I must be doing something wrong answer doesn't match examples of what it should be close to.
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Nigatsu_Aka
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Re: Maths Question
Grand Admiral Martin wrote:P = (Ln (220) x (220)2) + (220)
Where: Ln = Logarithm Neperian
P = (Ln (220) x (48,400) + (220)
Where: Ln = Logarithm Neperian
P = (Ln x 10,648,000) + (220)
Where: Ln = Logarithm Neperian
= ???
Can anyone finish that? I have tried but I must be doing something wrong answer doesn't match examples of what it should be close to.
You calculated wrong.
Here`s how you should do it:
IF you meant (220)2 = 220*220 THEN
P = (Ln(220) x 220^2) + 220 <=>
P = (5.39 x 48400) + 220 <=>
P = 260876 + 220 <=>
P = 261096
-----------------------------------------
IF you meant (220)2 = 220*2 THEN
P = (Ln(220) x 220x2) + 220 <=>
P = (5.39 x 440) + 220 <=>
p = 2371.6 + 220 <=>
p = 2591.6
Enjoy.
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deni
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Re: Maths Question
Nigatsu_Aka wrote:Grand Admiral Martin wrote:P = (Ln (220) x (220)2) + (220)
Where: Ln = Logarithm Neperian
P = (Ln (220) x (48,400) + (220)
Where: Ln = Logarithm Neperian
P = (Ln x 10,648,000) + (220)
Where: Ln = Logarithm Neperian
= ???
Can anyone finish that? I have tried but I must be doing something wrong answer doesn't match examples of what it should be close to.
You calculated wrong.
Here`s how you should do it:
IF you meant (220)2 = 220*220 THEN
P = (Ln(220) x 220^2) + 220 <=>
P = (5.39 x 48400) + 220 <=>
P = 260876 + 220 <=>
P = 261096
-----------------------------------------
IF you meant (220)2 = 220*2 THEN
P = (Ln(220) x 220x2) + 220 <=>
P = (5.39 x 440) + 220 <=>
p = 2371.6 + 220 <=>
p = 2591.6
Enjoy.
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